Question

If 16x2 24x r 0 have equal roots then find the value of r

Answer 1

Answer:

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Answer 2

If $16x^{2}\pm 24x+r=0$ has equal roots, then the value of r is 9.

Step-by-step explanation:

Problem 1.

$16x^{2}-24x+r=0$

For equal roots, we write the following condition,

$(-24)^{2}-4\times 16\times r=0$

$\Rightarrow 576-64r=0$

$\Rightarrow 64r=576$

$\Rightarrow r=\dfrac{576}{64}$

$\Rightarrow r=9$

Problem 2.

$16x^{2}+24x+r=0$

For equal roots, we write the following condition,

$(24)^{2}-4\times 16\times r=0$

$\Rightarrow 576-64r=0$

$\Rightarrow 64r=576$

$\Rightarrow r=\dfrac{576}{64}$

$\Rightarrow r=9$

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