Math, asked by Irham, 1 year ago

If 17^1/5x = 289 find the value of x

Answers

Answered by sarayulemon

3

17^*1/5 x=289
289*1/5 x=289
289*x=289*5 (transpose 1/5)
289*x=1445
x=1445/289 (transpose 289)
x=5

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