If √17+12√2/√11+√72=a+b√2,then what is the value of (a+3b) ?
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(17+12√2)
√√(17+2√(2*36)) when we take 6 inside sq root it becomes 36
√√(17+2√72)
√√(√9+√8)^2 split 72 in 9*8
√(3+2√2)
√(√1+√2)^2
1+√2
hope it helps
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