Math, asked by payel0278, 23 days ago

If √17+12√2/√11+√72=a+b√2,then what is the value of (a+3b) ?​

Answers

Answered by nishabhatti7362
0

Answer:

(17+12√2)

√√(17+2√(2*36)) when we take 6 inside sq root it becomes 36

√√(17+2√72)

√√(√9+√8)^2 split 72 in 9*8

√(3+2√2)

√(√1+√2)^2

1+√2

hope it helps

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