if 17.75×10^-12C of charge is placed at the centre of the cube, then find flux bounded to the cube.
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Explanation:
Total flux coming out =
ϵ
0
Q
enclosed
∫E.ds=
ϵ
0
Q×10
−6
(guass law)
As Q is placed at center, flux coming out of all sides will be equal.
∴ flux from one of the side =
6ϵ
0
Q×10
−6
=
6ϵ
0
Q×10
−6
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