if 17 th term of an A.P exceeds its 10 term by 14 then the common difference is ?
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Let us take the first term as a then nth term is a+(n-1)d So 10th term is a+9d and 17th term is a+16d , the difference is (a+16d)-(a+9d)=>7d=14 =>d=2. Common difference is 2.Hope it helps you.
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a17 = a10 +14 ; d = ?
a +16d = a+9d+14
16d -9d = 14
7d = 14
d = 14/7
d = 2 ( Ans )
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