Question

if 1728 = 2*2*2*3*3*3*2*2*2 then square root(3)(1728) is

Answer 1

Answer:

Step-by-step explanation:

FAQs on Cube Root of 1728

We can express 1728 as 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3 i.e. ∛1728 = ∛(2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3) = 12. Therefore, the value of the cube root of 1728 is 12.