If 17cosA=15..find the value of tanA+2SecA
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cosA=15/17=Base/hypotenuse
by using pythagorous theorem
(17)^2=(15)^2+p^2
p^2=(17)^2-(15)^2
p^2=289-225
p^2=64
perpendicular =8
now,tanA = perpendicular /base
tanA =8/17
secA =1/cosA=17/15
tanA +2secA =8/17+2×17/15 =698/255
by using pythagorous theorem
(17)^2=(15)^2+p^2
p^2=(17)^2-(15)^2
p^2=289-225
p^2=64
perpendicular =8
now,tanA = perpendicular /base
tanA =8/17
secA =1/cosA=17/15
tanA +2secA =8/17+2×17/15 =698/255
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