if 17sintheta=8 then value of 2tan theta÷1+tan square theta
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8 /17
2tantheta divided by 1 plus tan square theta
=sinthete
=8/17
2tantheta divided by 1 plus tan square theta
=sinthete
=8/17
kudupuganti1:
sorry wrong
Answered by
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Heya !!!
17 Sinø = 8
Sinø = 8/17 = Perpendicular/Hypotenuse.
Perpendicular = 8 and Hypotenuse = 17
By pythagoras theroem,
(H)² = (B)² + (P)²
(B)² = (H)² - (P)²
(B)² = (17)² - (8)²
(B)² = 289 - 64
(B)² = 225
B = ✓225 = 15
Therefore,
Tanø = Perpendicular/Base = 8/15
2 Tanø / 1 + Tan²ø => 2 × 8/15 / 1+ (8/15)²
=> 16/15 / 1 + 64/225
=> 16/15 / 225 +64 /225
=> 16 / 15
__________
289/225
=> 16/ 15 × 225/ 289
=> 16 × 15/ 289
=> 240/289
HOPE IT WILL HELP YOU...... :-)
17 Sinø = 8
Sinø = 8/17 = Perpendicular/Hypotenuse.
Perpendicular = 8 and Hypotenuse = 17
By pythagoras theroem,
(H)² = (B)² + (P)²
(B)² = (H)² - (P)²
(B)² = (17)² - (8)²
(B)² = 289 - 64
(B)² = 225
B = ✓225 = 15
Therefore,
Tanø = Perpendicular/Base = 8/15
2 Tanø / 1 + Tan²ø => 2 × 8/15 / 1+ (8/15)²
=> 16/15 / 1 + 64/225
=> 16/15 / 225 +64 /225
=> 16 / 15
__________
289/225
=> 16/ 15 × 225/ 289
=> 16 × 15/ 289
=> 240/289
HOPE IT WILL HELP YOU...... :-)
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