Question

If 17th term of an A.P. exceeds its 10th term by 14, then find the common difference.​

Answer 1

Answer:

2

Step-by-step explanation:

Given, a17 exceeds a10 by 14.

then , a17 - a10 = 14

a + 16d - a - 9d = 14

7d = 14

d. = 2

Answer 2

Answer:

d = 2

Step-by-step explanation:

let the 17th term = a+16d

let the 10th term = a+9d

so acc. to question,,

a+16d = a+9d+14

7d = 14

so,, d = 2 ....ans.