Question

If 17th term of an A. P exceeds its 10th term by 7. find the common difference.

Answer 1

Let a be the first term and d be the common difference of A.P.

17th term of A.P t17 = a + 16d.

10th term of A.P is t10 = a + 9d.

Given that 17th term of an A.P exceeds its 10th term by 7.

a + 16d = a + 9d + 7

7d = 7

∴ d = 1

Answer 2

hey user!

17th term = a + 16d
10th term = a + 9d

According to question ----
17th term - 10th term = 7
a + 16d - ( a + 9d) = 7
a + 16d - a - 9d = 7
7d = 7
d = 1

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