Question

if 18,a,(b-3) are in the ap,then find the value of (2a-b).

Answer 1

HELLO DEAR,

given that:-

t1=18

t2=a

t3=(b-3)

we know that:-
in AP

d=t2-t1 = t3-t2

a-18=b-3-a

=> a+a-b= -3+18

= > (2a-b) =15


I HOPE ITS HELP YOU DEAR,
THANKS

Answer 2

The value of $2a-b=15$

Step-by-step explanation:

Given :  If 18,a,(b-3) are in the A.P.

To find : The value of (2a-b) ?

Solution :

In an A.P. the difference between two consecutive terms is same.

The first term is $a_1=18$

The second term is $a_2=a$

The third term is $a_3=b-3$

So, $a_2-a_1=a_3-a_2$

$a-18=b-3-a$

$a+a-b=-3+18$

$2a-b=15$

Therefore, the value of $2a-b=15$

#Learn more

In an AP an= 3+5n. Find the AP​

https://brainly.in/question/11889544