Question

If 18 women can do a piece of work in 12 days and 12 men can do the same piece of work in 9 days. How many days will it take if 8 men and 8 women do the work together?​

Answer 1

Answer:

Correct Answer:

A) 9 days

Description for Correct answer:

12 men = 18 women

= 1 man = 1812 women = 32 women

Therefore, 8men = 32×8 = 12 women

Therefore, 8men + 16 women = 12 women + 16 women = 28 women

Therefore, 18 women can do the work in 14 days

Therefore, 1 woman can do the same work in 14×8 days.

Therefore, 28 women can do the same work in 14×1828 days.

Therefore, Required number of days = 14×1828 = 9 days

Step-by-step explanation:

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Answer 2

12 men = 18 women

= 1 man =

$\frac{18}{12}$

women =

$\frac{3}{2}$

women

Therefore, 8men =

$\frac{3}{2}$

×8 = 12 women

Therefore, 8men + 16 women = 12 women + 16 women = 28 women

Therefore, 18 women can do the work in 14 days

Therefore, 1 woman can do the same work in 14×8 days.

Therefore, 28 women can do the same work in

$\frac{14×18}{28}$

days.

Therefore, Required number of days =

$\frac{14×18}{28}$

= 9 days