Question

if π=180 and A=π/6 then prove that (1+cosA)(1-cosA)/(1-sinA)(1+sinA)=1/3​

Answer 1

Answer:

π = 180

A = π/6 = 30°

(1+cosA)(1-cosA)/(1+sinA)(1-sinA) = 1/3

LHS

⇒1 - cos²A/1 - sin²A

⇒Sin²A/Cos²A

⇒Tan²A

⇒(TanA)²

⇒(Tan30)²

⇒1/3

∴LHS=RHS

Answer 2

Step-by-step explanation:

given:

π=180 & A=π/6

so, A=30°

Taking L.H.S

(1+COS30°)(1-COS30°)/(1-sin30)(1+sin30)

(1)²-(cos30)²/(1)²-(sin30)²

1-3/4/1-1/4

1/4/3/4

1/3_Ans

L.H.S=R.H.S

HENCE_PROOVED

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