Question

if π = 180° A= π/3 and B= π/6 then prove that tan(A-B) = tanA -tanB/ 1 + tanA.tanB


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Answer 1

Answer:

Step-by-step explanation:

A = 60°

B = 30°

Tan(A-B) = TanA - TanB/1 + TanATanB

Tan(60-30) = Tan60 - Tan30/1+ Tan60Tan30

now,

Tan(30) = √3 - (1/√3)/1+ (✓3×1/√3)

Tan 30 = (3- 1/√3)/1+1

Tan 30 = 2/√3×1/2

Tan30 = 1/√3

therefore LHS = RHS, hence proved