if 180°<theta<270°and cos theta =-3/5,then tan theta /2
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cos$=-3/5=b/h
b=-3 and h=5
by pythagoras theorem:
h²=b²+p²
(5)²=p²+(-3)
p²=25-9=16
p=4
tan$/2=p/2b=4/(2×(-3))=-2/3 answer
please mark me brainliest.
b=-3 and h=5
by pythagoras theorem:
h²=b²+p²
(5)²=p²+(-3)
p²=25-9=16
p=4
tan$/2=p/2b=4/(2×(-3))=-2/3 answer
please mark me brainliest.
NightingaleMadhu:
Thanks for answering but the answer is not there in the options the options are a.-1 b.-2 c.2 d.1 please find
Answered by
4
Answer:
i didnt get u in last step
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