If 180xp =q^2 then least value for pq
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Let z = x^2-x+1x^2+x+1 z = x^2+x+1-2xx^2+x+1 z = x^2+x+1x^2+x+1 - 2xx^2+x+1 z = 1 - 2xx^2+x+1 Let y = 2xx^2+x+1 dydx = (x^2+x+1) × 2 - (2x) (2x ...
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the above one is the right answer of your question
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