Question

If 184 is divided into two parts such that
one-third of one part exceeds one-seventh of
the other part by 8, then the greater part is
(A) 72 (B) 110 (C) 112 (D) 114​

Answer 1

Step-by-step explanation:

Let the one part be x. Then, the other part will be184−x. According to question, 13×x=17(184−x)+8⇒x3=1847−x7+8 ⇒x3+x7=1847+8⇒10x21=2407 ⇒ x=240×217×10=72 ∴First part = 72 and

secon part =184−72=112

Answer 2

Answer:

answer is c) 112

Step-by-step explanation:

(x/3) - (184 - x)/7 = 8

x/3 - (184 -x)/7 = 8

7x - 552 + 3x = 3 × 7 × 8

7x - 552 + 3x = 168

10x = 552 + 168

10x = 720

x = 720/10

x = 72

The one parts is 72

The other part is 184 - 72 = 112.