Question

if 18g of glucose is present in 1000g of solvent then what is its molarity

Answer 1

molarity=mole of solute/volume of solution in litres
no. of moles of glucose =mass of glucose /molar mass of glucose
molar mass of glucose =180g/mol
no. of moles of glucose =18/180=1/10mol
1 m³=1000 litre=1000000g
10^6g =10³ litre
10³ g =1 litre
molarity of solution =1/10÷1=1/10 mol/litre

Answer 2

Answer:

here is the answer for your question