Question

If 18m is a multiple of 3 where m is a digit, what might be the values of m?
Pls answer it if anyone gives correct answer first I will mark him brainliest​

Answer 1

Answer:

Solution

verified

Since the number 21y5 is a multiple of 9.

So, the sum of its digits 2+1+y+5=8+y is a multiple of 9.

∴(8+y) is either 0 or 9 or 18 or ...

Since y is a digit, so (8+y) must be equal to 9.

i.e., 8+y=9

⇒y=9−8=1

Answer 2

Step-by-step explanation:

1+8+m=multiple of 3

so probabilities are

3,6,9