If 19 main scale divisions coincides with 20 vernier scale divisions the least count will be (1 MSD=1mm)
Answers
Answered by
2
Hii dear,
◆ Answer -
LC = 0.05 mm
◆ Explaination-
Consider,
MSD = main scale division
VSD = vernier scale division
# Given -
MSD = 1 mm
20 VSD = 19 MSD
VSD = 19/20 MSD
# Solution -
Least count of instrument
LC = 1 MSD - 1 VSD
LC = 1 MSD - 19/20 MSD
LC = 1/20 MSD
LC = 1/20 × 1
LC = 0.05 mm
Hence, least count of vernier calliper is 0.05 mm.
Hope that was useful...
Answered by
0
Answer:
LC= 0.05 mm
Explanation:
Hope it is helpful
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