Question

If 196×10 j of energy were used to raise a 20kg boy above the ground,how high would he be raised? (Given g=9.8 ms-2)

Answer 1

Given:

Energy=$196\times 10^2 J$

Mass of boy,m=20 kg

$g=9.8ms^{-2}$

To find :

Height raised from the ground

Solution:

We know that

P.E=$mgh$

Where m=Mass of body

h=Height of body

g=Acceleration due to gravity

Using the formula

$196\times 10^{2}=20\times 9.8 h$

$h=\frac{196\times 10^{2}}{20\times 9.8}$

$h=100 m$

Hence, height of boy above the ground raised =100m