Question

if 1960 = 2a × 5b× 7c , find the value of a,b,c​

Answer 1

Step-by-step explanation:

first of all find factors of 1960

1960=2³×5×7²

compare this with 2a×5b×7c

in place of 1960 we write 2³×5×7²

2³×5×7²=2a×5b×7c

base are same so on comparing with powers

a=3 b=1 C=2

Answer 2

Step-by-step explanation:

if 1960= 2a×5b×7c

1960 = 2×2×2×5×7×7 (lcm of 1960 )

= 2^3 ×5^1 ×7^2 ( ^ = square , 2 square 3,

5 square 1, 7 square 2 )

2^3 × 5^1 ×7^2 = 2a × 5b × 7c

so , a=3 , b=1, c=2