Question

if 196gm H2SO4 IS disolved in 720gm water then calculate the mole fraction of component(H=1,S=32,O=16)​

Answer 1

Mole fraction of water = 0.95 and Mole fraction of sulphuric acid = 0.047

Explanation:

Mole fraction of a component is the ration of number of moles of that component to the total number of moles in the solution.

• Weight of $H_2SO_4$ = 196 g

• Molecular weight of $H_2SO_4$ = $1 \times2 + 32 + 16 \times 4 =2+32+64=98$  

• Weight of water = 720 g

• Molecular weight of water = $1 \times 2+16=18$

• $Number\, of\, moles=\frac{Weight}{Moleculatr\,weight}$

• $\therefore No.\,of\,moles\,of\,H_2SO_4=\frac{196}{98} =2\\No.\,of\,moles\,of\,water=\frac{720}{18} =40$  

• $Mole\,fraction\,of\,H_2SO_4=\frac{2}{2+40} =\frac{2}{42} =0.047$

• $Mole\,fraction\,of\,water=\frac{40}{2+40} =\frac{40}{42} =0.95$