if 19th term is 200 and 9th term is 100 find AP
hatimlaila23:
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THE ANSWER IS
SUM =A+(N-1)D
A=FIRST TERM
D=DIFFERENCE
200=A+(18)D-----1
100=A+(8)D--------2
SOLVING 1 AND 2
100=10D
D=10-----3
SUBSTITUTING 3 IN 1
200=A+180
A=20
AP=A,A+D,A+2D
=20,30,40,50........
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