If 1A2B5 is exactly divisible by 9, then the least value is(A+B)
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Answer:Any number to be divisible by 9, the sum of its digits should also be divisible by 9.
1+A+2+B+5 = 8+A+B
8+A+B = 9
A+B = 9–8 = 1
So, 1 is the least value of A+B. (Where the two digits are 0 & 1).
The original number could be 10215 / 11205 only when A+B is the least value, as shown above.
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Answer:
If 1A2B5 is exactly divisible by 9, then the least value is(A+B) is 1
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