if -1and1 are zeroes of 2x4+qx3+3x+p,then find the value of square of p+q
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p(x) = 2x⁴ + qx³ + 3x + p
- 1 = 2(-1)⁴ + q(-1)³ + 3(-1) + p
- 1 = 2 - q - 3 + p
- 1 - 2 + 3 = p - q
0 = p - q -------(1)
1 = 2(1)⁴ + q(1)³ + 3(1) + p
1 = 2 + q + 3 + p
- 4 = p + q --------(2)
On adding botg equation we get
- 4 = p
Keep value of p in eqn 2
- 4 = p - q
- 4 + 4 = - q
0 = q
Hence, p + q => - 4 + 0 = - 4
нσρє ιт нєℓσѕ
нєяє ιѕ уσυя ѕσℓυтισи
p(x) = 2x⁴ + qx³ + 3x + p
- 1 = 2(-1)⁴ + q(-1)³ + 3(-1) + p
- 1 = 2 - q - 3 + p
- 1 - 2 + 3 = p - q
0 = p - q -------(1)
1 = 2(1)⁴ + q(1)³ + 3(1) + p
1 = 2 + q + 3 + p
- 4 = p + q --------(2)
On adding botg equation we get
- 4 = p
Keep value of p in eqn 2
- 4 = p - q
- 4 + 4 = - q
0 = q
Hence, p + q => - 4 + 0 = - 4
нσρє ιт нєℓσѕ
BhavyamThakur:
because answer is 25
Oh wait
but thanku
I think u have written queston wrong
Please check it again
now i know how to do this
nhi question is right
okay
please do next question
suchi
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