Question

if 1cm height of the object is place at a distance 7.5cm is front of concave mirror then its real Image is from having the height two times that object hight calculate the image disatance, focal length, and magnification of concave mirror. ​

Answer 1

Answer:

Given: Concave mirror f=−10cm and m=−2 height of object=h

Solution: Since m=

u

−v

=2=

h

hi

v=−2u

So, from mirror formula

v

1

+

u

1

=

f

1

v

u

=

f

u

−1

m=

u

−v

=

f−u

f

Since m=−2=

f−u

f

−2f+2u=f

u=

2

3f

=−15cm

u=−15cm And m=−2=

u

−v

So v=−30cm