Question

If 1g of sulphur dioxide contains X molecules, what will be the number of molecules in 1g of methane ?
(S= 32u, O= 16u, C= 12u, H= 1u)

Answer 1

Molar mass of sulphur dioxide = 64g
Moles in 1g of sulphur dioxide = 1/64 mole
No. of molecules = x = 9.4*10²¹ molecules
Molar mass of methane = 16g
Moles in 1g of methane = 1/16 mole
No. of molecules = 37.6*10²¹ molecules
= 37.6*10²¹/9.4*10²¹ = 4x

Answer 2

Explanation:

first change gram to mole.

mole=given mass/molar mass.

=1/64

how 64 came?

so2=32+16*2

=64mol

the molecules of both compound will be same.

CH4= 12+1*4

=16

16mol

mole of 16g of methane=1mol

mole if 1g of methane =1/64mol

x*64/16=4x molecules