Question

If 1is a zero of the polynomial p(x) =ax2 -3(a-1)x-1 find the value of (a )

Answer 1

Answer:

p(x)= ax2-3(a-1)x-1

p(x)=ax2-(3a+3)x-1

=a(1)^2-(3a+3)1-1=0

=a-3a-3-1=0

=-2a=3+1

=-2a=4

a=-2