if 1st,2nd and last term are respectively a,b and 2a of an AP ,then prove that sum of progression will be (3ab)/2(b-a).
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Step-by-step explanation:
Common difference =b—a
2a =a+(n–1) (b–a)
a/b–a =n–1
a/b–a +1 = n
a+b–a/b–a = n
b/b–a =n
sum of ap n/2 ( x+2a)
3ab/2(b–a)
hence prove
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