Question

if 1st,2nd and last term are respectively a,b and 2a of an AP ,then prove that sum of progression will be (3ab)/2(b-a).​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Common difference =b—a

2a =a+(n–1) (b–a)

a/b–a =n–1

a/b–a +1 = n

a+b–a/b–a = n

b/b–a =n

sum of ap n/2 ( x+2a)

3ab/2(b–a)

hence prove