Question

If, 1st digit = x
2nd digit = y
3rd digit = z
So, Prove that for a number to be divisible by 5 its unit's digit should be divisible by 5.​

Answer 1

Answer:

1st digit = x

2nd digit = y

3rd digit = z

The number formed is 100z +10y + x

Here we can clearly see that we can take out 5 from 100z and 10y by taking 5 as common, like this 5(20z + 2y).

So if the number has to be divisible by 5 than the digit x should also contain a multiple of 5 so that we can take out 5 as common from all the three digits (i.e. the whole number).

And we know that the number divisible by 5 (in ones place) will be 5 itself or 0.

This is how we can say that x should be 5 or 0 (more importantly 5) so that the number gets divisible by 5.  

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