Question

If 2,0. 0,2. 0,-2,0 are three coodinate
Prove that they are the coodinate of a
triangle

Answer 1

AS THREE POINTS ARE NON COLINEAR IT FORMS A TRIANGLE

Answer 2

suppose A(2,0),B(0,2),C(-2,0) are the vertices of triangle

by calculating the distance between them we find the type of triangle

so,

d(A,B) =

=Under Root(X2-X1)^2+(Y2-Y1)^2

=underroot(0-2)^2+(2-0)^2

=underoot(-2)^2+(2)^2

=under root 4+4

=under root 8

=taking squre root

=2root2

now,

d(B,C)

=under root(X2-X1)^2+(Y2-Y1)^2

=under root(-2-0)^2+(0-2)^2

=under root 4+4

=2root2

now,

d(A,C)

=under root(X2-X1)^2+(Y2-Y1)^2

=under root(-2-2)^2+(0-0)^2

=under root(-4)^2

=under root 16

=4
now two sides of the triangle are equal
therefore this is
isosceles triangle