Math, asked by soccar2007, 5 months ago

If (2, 0) is a solution of the linear equation 2x-3y-k=0, then find the
value of k.​

Answers

Answered by TheUnpredictable
1
Answer:

Given that (2,0) is a solution of the linear equation 2x - 3y - k = 0.

Coordinates are written on the form (x,y)
=> x = 2 and y = 0

Use x = 2 and y = 0 in the given linear equation,

=> 2x - 3y - k = 0
=> 2(2) - 3(0) - k = 0
=> 4 - 0 - k = 0
=> 4 - k = 0
=> k = 4

Therefore, the value of k is 4.

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