If (2, 0) is a solution of the linear equation 2x-3y-k=0, then find the
value of k.
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Answer:
Given that (2,0) is a solution of the linear equation 2x - 3y - k = 0.
Coordinates are written on the form (x,y)
=> x = 2 and y = 0
Use x = 2 and y = 0 in the given linear equation,
=> 2x - 3y - k = 0
=> 2(2) - 3(0) - k = 0
=> 4 - 0 - k = 0
=> 4 - k = 0
=> k = 4
Therefore, the value of k is 4.
Please mark this answer as brainliest.
Given that (2,0) is a solution of the linear equation 2x - 3y - k = 0.
Coordinates are written on the form (x,y)
=> x = 2 and y = 0
Use x = 2 and y = 0 in the given linear equation,
=> 2x - 3y - k = 0
=> 2(2) - 3(0) - k = 0
=> 4 - 0 - k = 0
=> 4 - k = 0
=> k = 4
Therefore, the value of k is 4.
Please mark this answer as brainliest.
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