Question

If 2.00 mL of 0.200 m NaOH are added to 1.00 L of a 0.100 m caCl2 will a precipitate form?

Answer 1

If 2.00 mL of 0.200 m NaOH are added to 1.00 L of a 0.100 m caCl2 will a precipitate form?

If Q>KsP the PPT form

Ca2+ = 0.1 mol

mole of atm = 3×10-³ × 0.2

= 4×10-⁴

Total Volume = 0002+1 = 1.002

Q = [ Ca2+] [ OH] ²

= 1.6×10-⁸

Q<KSP

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Note :-

Q is denoting Theta