Question

If 2.02 g of coal is combusted in combustion tube. After passing the CO2, increase in weight of KOH tube is 5.88 gm. Hence % C present in coal is​

Answer 1

Answer:

The percentage of carbon present in the coil calculated is $79.38\%$.

Explanation:

Given data,

The weight of coal in the combustion tube, $W_{1}$ = $2.02$

After passing $CO_{2}$,

The increase in weight of $KOH$ tube, $W_{2}$ = $5.88g$

The percentage of carbon present in the coil =?

From the formula given below, we can find out the percentage of carbon present in the coil:

• % C = $\frac{W_{2}\times 12\times 100 }{W_{1}\times 44 }$

After putting the given values of weights in the equation, we get:

• % C = $\frac{5.88\times 12\times 100 }{2.02\times 44 }$
• % C = $\frac{7056 }{88.88 }$
• % C = $79.38\%$

Hence, the percentage of carbon present in the coil = $79.38\%$.

Answer 2

Given,

2.02 g of coal is combusted in the combustion tube.

After passing $CO_2$, KOH increases by 5.88 g

To find,

The % C present in coal.

Solution,

We can find the answer to this question easily since we know,

% C = $\frac{ W_2X12X100}{W_1X44}$

where $W_1$ is the increased weight and

$W_2$ is the weight of the coal.

lets put the values of $W_1$ and $W_2$ in the equation

% C = $\frac{ 5.88X12X100}{2.02X44}$

⇒ % C = 79.38 %

∴ The % C present in the coal is 79.38 %