Question

If (×)2 + (1/(×)2 =27 find the value if (×)4 + (1/(×)4.

Answer 1

$\huge\mathtt{\underline{\underline{\purple{SOLUTION:-}}}}$

it's given that the value of

$\sf\leadsto x{}^{2}+\frac{1}{x{}^{2}}=27$

To find:-

$\sf\implies x{}^{4}+\frac{1}{x{}^{4}}$

$\sf{\underline{\red{Identity\:used:-}}}$

$\sf (x+\frac{1}{x}){}^{2}=x{}^{2}+\frac{1}{x{}^{2}}+2\times x+\frac{1}{x}\\ \\ \sf\implies x{}^{2}+\frac{1}{x{}^{2}}+2$

• The process I used in this question
• 1st square both side and then we get something
• then solve our question it's too easy for solve .

Step by step explanation:-

$\large\sf\underline{\underline{\purple{According\:to\: Question:-}}}$

$\sf x{}^{2}+\frac{1}{x{}^{2}}=27\\ \\ \sf\implies squaring\: both\:sides\\ \\ \sf\leadsto (x{}^{2}+\frac{1}{x{}^{2}}){}^{2}=(27){}^{2}\\ \\ \sf\leadsto x{}^{4}+\frac{1}{x{}^{4}}+2=729\\ \\ \sf\leadsto x{}^{4}+\frac{1}{x{}^{4}}=729-2\\ \\ \sf\implies x{}^{4}+\frac{1}{x{}^{4}}=727$

The value of :-

$\sf{\blue{x{}^{4}+\frac{1}{x{}^{4}}=727}}$

#BAL

#Answerwithquality