If ²⁰∑ᵢ₌₁ [(²⁰C₍ᵢ₋₁₎)/(²⁰Cᵢ + ²⁰C₍ᵢ₋₁₎)]³ = k/21, then k equals :
(A) 400 (B) 50
(C) 200 (D) 100
Answers
Answered by
1
ANSWER: (D) 100
HOPE IT HELPS YOU........
Attachments:
Answered by
1
Answer:
♥️꧁༒☬☠PRINCE☠︎☬༒꧂♥️
Step-by-step explanation:
CORRECT ANSWER ➡️ K = 100
Similar questions