Question

If 2 1/4 ÷ 1 1/2 of [4 1/6 - ( 17/21 + 1 1/3 × 2 1/8 ÷ 1 1/6 of 3/4 - 3/4 × 20/21)] = a/b, find 2a - 3b, given that H.C.F of a & b is 1.​

Answer 1

Solution :-

→ 2 1/4 ÷ 1 1/2 of [4 1/6 - ( 17/21 + 1 1/3 × 2 1/8 ÷ 1 1/6 of 3/4 - 3/4 × 20/21)] = a/b

→ (9/4) ÷ (3/2) of [(25/6) - {(17/21) + (4/3) × (17/8) ÷ (7/6) of (3/4) - (3/4) × (20/21)] = a/b

→ (9/4) ÷ (3/2) of [(25/6) - {(17/21) + (4/3) × (17/8) ÷ (7/8) - (5/7)}] = a/b

→ (9/4) ÷ (3/2) of [(25/6) - {(17/21) + (4/3) × (17/7) - (5/7)}] = a/b

→ (9/4) ÷ (3/2) of [(25/6) - {(17/21) + (68/21) - (5/7)}] = a/b

→ (9/4) ÷ (3/2) of [(25/6) - (17 + 68 - 15)/21] = a/b

→ (9/4) ÷ (3/2) of [(25/6) - (70/21)] = a/b

→ (9/4) ÷ (3/2) of [(25 - 20)/6] = a/b

→ (9/4) ÷ (3/2) of (5/6) = a/b

→ (9/4) ÷ (3/2) × (5/6) = a/b

→ (9/4) ÷ (5/4) = a/b

→ (9/4) * (4/5) = a/b

→ (9/5) = a/b .

since HCF of a and b is 1 , we can assume a as 9 and b as 5 .

then,

→ 2a - 3b

→ 2 * 9 - 3 * 5

→ 18 - 15

→ 3 (Ans.)

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