Question

If √2 =1.41, then √2-1/√2+1 = _______ Using rationalising the denominator.​

Answer 1

Answer:

Given,

$\sqrt{2} = 1.41$

To find  ⇒   $\frac{\sqrt{2}- 1 }{\sqrt{2}+1}$

$\frac{\sqrt{2} - 1 }{\sqrt{2}+ 1} = \frac{\sqrt{2} - 1 }{\sqrt{2}+ 1}.\frac{\sqrt{2} - 1 }{\sqrt{2}-1}$

        $= \frac{(\sqrt{2} - 1) . (\sqrt{2}-1) }{(\sqrt{2}+ 1). (\sqrt{2}-1)}$

        $=\frac{(\sqrt{2})^2 - 2*\sqrt{2} *1 + 1^2 }{(\sqrt{2})^2 - 1^2 }$

        $=\frac{2 - 2\sqrt{2} + 1}{2 - 1}$

        $=\frac{1 - 2 * 1.41}{1}$

        $= 1 - 2.82$

        $= - 1.82$

             Hope it helps you^_^      

Answer 2

Answer:

hii army

Step-by-step explanation:

This is sandya

tell your pinterest id We can talk there my friend