If √2 = 1.414 , √3 = 1.732 and √5 = 2.236 then find values of
1) √98
2) √128 + √48
3) 2√75 - 3√12
Answers
Answered by
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Answer:
1) √98 = 7√2
= 7 x 1.414 = 9.898
2) √128+√48 = 8√2 + 4√3
= (8x1.414) + (4x1.732)
= 11.312 + 6.928
= 18.24
3) 2√75-3√12 = 10√3-6√3
= (10x1.732)-(6x1.732)
= 17.32-10.392
= 6.928
Answered by
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Step-by-step explanation:
2 = 1.414 ,
√3 = 1.732
and
√5 = 2.236
1) √98
= √(7×7×2)
= 7(√2)
=7× 1.414
= 9.898
2) √128 + √48
= √ (8×8×2) + √( 4×4×3)
= 8√2+4√3
= 8× 1.414+4×1.732
= 11.3 12+ 6.928
= 18.240
3) 2√75 - 3√12
= 2√(3×5×5)-3√(2×2×3)
= 2×5√3-3×2√3
= 10√3-6√3
= 4√3
= 4×1.732
= 6.928
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