Question

If √2 = 1.414 , √3 = 1.732 and √5 = 2.236 then find values of
1) √98
2) √128 + √48
3) 2√75 - 3√12​

Answer 1

Answer:

1) √98 = 7√2

= 7 x 1.414 = 9.898

2) √128+√48 = 8√2 + 4√3

= (8x1.414) + (4x1.732)

= 11.312 + 6.928

= 18.24

3) 2√75-3√12 = 10√3-6√3

= (10x1.732)-(6x1.732)

= 17.32-10.392

= 6.928

Answer 2

Step-by-step explanation:

2 = 1.414 ,

√3 = 1.732

and

√5 = 2.236

1) √98

= √(7×7×2)

= 7(√2)

=7× 1.414

= 9.898

2) √128 + √48

= √ (8×8×2) + √( 4×4×3)

= 8√2+4√3

= 8× 1.414+4×1.732

= 11.3 12+ 6.928

= 18.240

3) 2√75 - 3√12

= 2√(3×5×5)-3√(2×2×3)

= 2×5√3-3×2√3

= 10√3-6√3

= 4√3

= 4×1.732

= 6.928