Question

if √2=1.414,√3=1.732,then find the value of√6÷√3-√2​

Answer 1

Answer:

2=1.414,√3=1.732,then

Step-by-step explanation:

1.414,√3=1.732,then find the value of√6÷√3-√2

Answer 2

Answer:

The answer is $0.778$

Step-by-step explanation:

Given $\sqrt2=1.414$ and $\sqrt 3=1.732$

Thus

        $\dfrac{\sqrt 6}{\sqrt 3-\sqrt 2}\times \dfrac{\sqrt 3+\sqrt 2}{\sqrt 3+\sqrt 2}$  , rationalize the denominator

      $=\dfrac{\sqrt {18}-\sqrt{12}}{(\sqrt 3)^2-(\sqrt 2)^2}\\\\=\dfrac{\sqrt{9(2)}-\sqrt{4(3)}}{3-2}\\\\=\dfrac{\sqrt 9\sqrt 2-\sqrt 4\sqrt 3}{1}\\=3\sqrt 2-2\sqrt 3\\=3(1.414)-2(1.732)\\=4.242-3.464=0.778$