if (-2,-1),(a,0),(4,b)and (1,2)are the vertices of a parallelogram then a=
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Let A(-2,1), B(a, 0), C(4, b) and D(1,2) be the vertices of a parallelogram. Since, diagonals of parallelogram bisect each other. .'. Let E(x, y) be the point where diagonals bisect each other. Hence, coordinates of E from AC (i) Value of a = 1 (ii) Value of b = 1 (iii) Area of parallelogram ABCD = Area of ΔABC +Area of ΔACD Now, area of ΔABC = 3 sq. units Area of ΔACD = 3 sq. units Area of parallelogram = 3 + 3 = 6 sq. units.
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