Question

if (2,-1) is a solution of 6x-5y+k=0 find the value of k​

Answer 1

Answer:

k=−3

Step-by-step explanation:

The equation are

2kx+5y−7=0

6x−5y−11=0

Here, a1=2k,b1=5,c1=−7

and a2=6,b2=−5,c2=−11

Forthesystemtohaveuniquesolution

⇒a2a1=b2b1

⇒62k=−55

⇒2k=−6⇒k=−3  

Answer 2

Answer:

-17

Step-by-step explanation:

given:-

(2, -1) =(x, y)

6x-5y+k=0

put that value in equation

6×2 -5×(-1) +k=0

12+5+k=0

k= -17