If (- 2, 1) is the centroid of the triangle having its vertices at (x , 2) , (10 , -2) , (-8 , y) , then x , y satisfy the relation *
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2
• Co ordinates of Centroid of ∆ ABC with A ( x1,y1 ) , B ( x2,y2 ) , C ( x3,y3 ) as its vertices is
=> [ ( x1 + x2 + x3 ) / 3 , ( y1 + y2 + y3 ) / 3 ]
So ,
=> according to question ,
=> -2 = { x + 10 + (-8) } / 3
=> -6 = x + 10 - 8
=> -6 = x + 2
=> x = -8 ...
And , => 1 = { 2 + (-2) + y } / 3
=> 3 = 2-2 + y
=> y = 3 ....
therefore , x = -8 and y = 3
Answered by
2
Answer:
x=-8
y=3
Step-by-step explanation:
given
centroid= (- 2, 1)
vertices of the triangle=
(x , 2) , (10 , -2) , (-8 , y)
find x,y
centroid of the triangle having vertices (x1,y1),(x2,y2),(x3,y3)
(x1+x2+x3/3,y1+y2+y3/3)
(x+10-8/3,2-2+y/3)=(- 2, 1)
x+10-8/3=-2
x+2=-6
x=-2-6
x=-8
2-2+y/3=1
0+y=3
y=3
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