If = √2 + 1 , then find the value of
(i) ( −1/)2(square)
(ii) 3(cube) +1/3(cube)
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Answer:
Given, x=2+2
2/3
+2
1/3
⇒(x−2)=2
2/3
+2
1/3
⇒(x−2)=2
2/3
+2
1/3
On cubing both sides, we get
(x−2)
3
=2
2
+2+3⋅2
2/3
⋅2
1/3
(2
2/3
+2
1/3
)
⇒x
3
−6x
2
+12x−8=4+2+3×2×(x−2)
⇒x
3
−6x
2
+6x=2.
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