Math, asked by valvel137, 9 months ago

) If 2 2 1 x 7 x   , find the value of 3 3 1 x x 

Answers

Answered by Anonymous
6

Answer:

Given Equation is x^2 + 1/x^2 = 7

We know that (x + 1/x)^2 = x^2 + 1/x^2 + 2 * x * 1/x

                                         = x^2 + 1/x^2 + 2

                                        = 7 + 2

                                        = 9

                          (x + 1/x) = 3

Now,

(x^3 + 1/x^3) = (x + 1/x)^3 - 3 * x * 1/x * (x + 1/x)

                     = (x + 1/x)^3 - 3(x + 1/x)

 

                    = (3)^3 - 3(3)

                   = 27 - 9

                   = 18.

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