If 2+2=100 =20, ℎ (−)2
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If 2+2=100 =20, ℎ (−)2
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Computation of Median
Class interval Frequency (f) Cumulative frequency (cf)
0-100 2 2
100-200 5 7
200-300 x 7+x
300-400 12 19+x
400-500 17 36+x
500-600 20 56+x
600-700 y 56+x+y
700-800 9 65+x+y
800-900 7 72+x + y
900-1000 4 76+x + y
Total = 100
We have,
N=∑f
i
=100
⇒76+x+y=100⇒x+y=24
It is given that the median is 525. Clearly, it lies in the class 500−600
∴l=500,h=100,f=20,F=36+x and N=100
⇒525−500=(14−x)×5
⇒25=70−5x⇒5x=45⇒x=9
Putting x=9 inx+y=24, we get y=15.
Hence, x=9and y=15.
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