If 2ᵐ⁺ⁿ/2ⁿ⁻ᵐ = 16 , and a = 2¹៸¹⁰ , then a²ᵐ⁺ⁿ⁻ᵖ/(aᵐ⁻²ⁿ⁺²ᵖ) ⁻¹ =
A. 2
B.
C. 9
D.
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Answer:
i think its answer will be 2
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