Question

If , 2 + 2, 3 + 3 are the first three terms of a geometric progression, then 4 term in the geometric progression is

Answer 1

Answer:

i hope help this answer...

Answer 2

Answer:

As x, 2x + 2, 3x + 3 are in G.P.

$(2x + 2) {}^{2} = x \times (3x + 3) = > 4x {}^{2} + 8x + 4 = 3x {}^{2} + 3x$

$= > x {}^{2} + 5x + 4 = 0 = > \\ (x + 1)(x + 4) = 0 = > x = - 1 \: or \: - 4$

Using x = - 1,we get first three terms as - 1,0,0.

which is not possible as in a G.P. all terms are non - zero.

Using x = - 4, we get first three terms as

- 4,- 6,-9. which is a G.P. with common ratio.

r = 3/2.

Hence, the 4th term =

(3rd term) × common ratio

(- 9) (3/2) = -27/2.

Step-by-step explanation:

@Genius