Question

If 2.25 x 10 raise to power 20 electrons pass through a wire in one minute, find the magnitude of the current flowing through the wire.

Answer 1

Answer:

0.6 A

Explanation:

I=ne/t

=2.25×10^20×1.6×10^-19/60

Answer 2

Q=Ne=2.25×10^20×1.6×10^-19=36C

t=1min=60s

Current=Q/t=36/60=0.6A